Sabtu, 05 April 2008

Siswa yang remidi kelas X-1 lat. 4.3

1. Abed 10. Stevico
2. Angela 11. Yohanes
3. Gaby 12. Christin
4. Gita 13. Christ
5. Ryth 14. Hendy
6. Rheine 15. Adrian
7. Stevan 16. Ferdi
8. Ivan 17. Yohanes N
9. Dendy
PERHATIAN ! REMIDI DIKERJAKAN PALING LAMBAT JUMAT, 11 APRIL 2008

10 komentar:

GoZ:: mengatakan...

Diket=
Vit.C = 528 mgram
CO2 = 792 mgram
H2O = 216 mgram
Mr V.C= 176
Ditanya=
Rumus Molekul??

Jawab= CxHyOz + O2 => CO2 + H2O
528 mg : 792 mg : 216 mg
massa C dari CO2= Ar C:Mr CO2×Massa CO2
= 12:44×792 mg
= 215,9 mg
= 216 mg(Pembulatan)
massa H dari H2O= 2.Ar H:Mr H2O×Massa H2O
= 2:18×216
= 23,9 mg
= 24 mg
massa C+massa H = 216 mg+24mg= 240mg
Total massa C+ massa H < massa Vit.C,
Hal ini menunjukan ada O2 dalam senyawa tersebut karena masih ada sisa massa di massa vitamin C.

Massa O= Massa Vit.C-massa C+massa H
= 528-240
= 288 mg

nC: nH: nO=
massa C : massa H : massa O
Ar C : Ar H : Ar O
= 216:24:288
= 18:24:16
= 3:4:3
Jadi:
rumus Empiris Vit.C= (C3 H4 O3)n

Mr Vit.C =176
Mr (C3H4O3)n=176
(3xArC+4xArH+3xArO)n=176
(3x12+4x1+3x16)n=176
(36+4+48)n=176
88n=176
n=2
Jadi rumus molekul Vit.C adalah :
C6H8O6
-ADRIAN GOZALI-
- X-1 / 2 -

ivanx1 mengatakan...

Cx Hy + ( x + ¼ y ) O2 x CO2 + ½ y H2O
528 480 792 216

Mol CO2 = 792 : 44 = 18 ( x = 18 )

Mol H2O = 216 : 18 = 12 ( 12 = ½ y )
(24 = y )
C18 H24
= C3H4 ( Rumus Empiris )

[ Cx Hy ] n = 176
[ C3 H4 ] n = 176
[ 12.3 + 1.4 ] n = 176
[ 36 + 4 ] n = 176
40 n = 176
n = 4,4

Rumus Molekul = [ C3H4 ] 4,4
= C13,2 H17,6
= C13 H20

Anonim mengatakan...

Nama: Angle Nathania S
Kls/No: X-1 / 05

Diket:
Massa Vitamin C = 528 mg
Massa CO2 = 792 mg
Gr H2O = 216 mg
Mr ( Molekul Relatif ) Vitamin C = 176

Dit:
Rumus Molekul

Jwb:
Cx Hy Oz + O2 => CO2 + H2O
528 mg + x => 792 mg + 216 mg

Massa C dari CO2 = Ar C / Mr CO2 x massa CO2
= 12 / 44 x 792 mg
= 215,9 mg
= 216 mg

Massa H dari H2O = 2 x Ar H / Mr H2O x massa H2O
= 2 x 1 / 18 x 216
= 1 / 9 x 216
= 23,9 mg
= 24 mg

Massa C + Massa H = 216 mg + 24 mg
= 240 mg
Total massa C + massa H = 216 mg + 24 mg
= 240 mg

Massa O = Massa vitamin C – ( massa C + massa H )
= 528 mg – 240 mg
= 288 mg

nC : nH : nO = massa C : massa H : massa O
ArC : ArH : ArO = 216/12 : 24/1 : 288/16
= 3 : 4 : 3

Rumus Empiris Vitamin C : ( C3 H4 O3 )
Mr Vitamin C = 176
Mr ( C3 H4 O3 )n = 176
( 3 x Ar C + 4 x Ar H + 3 x Ar O )n = 176
( 3 x 12 + 4 x 1 + 3 x 16 )n = 176
( 36 + 4 + 48 )n = 176
88n = 176
n = 176 / 88
n = 2
Rumus Molekulnya : (C3 H4 O3)2 atau C6 H8 O6

Anonim mengatakan...

Nama: Angela Nathania S
Kls/NO: X-1/05
Diket:
Massa Vitamin C = 528 mg
Massa CO2 = 792 mg
Gr H2O = 216 mg
Mr ( Molekul Relatif ) Vitamin C = 176

Dit:
Rumus Molekul

Jwb:
Cx Hy Oz + O2 => CO2 + H2O
528 mg + x => 792 mg + 216 mg

Massa C dari CO2 = Ar C / Mr CO2 x massa CO2
= 12 / 44 x 792 mg
= 215,9 mg
= 216 mg

Massa H dari H2O = 2 x Ar H / Mr H2O x massa H2O
= 2 x 1 / 18 x 216
= 1 / 9 x 216
= 23,9 mg
= 24 mg

Massa C + Massa H = 216 mg + 24 mg
= 240 mg
Total massa C + massa H = 216 mg + 24 mg
= 240 mg

Massa O = Massa vitamin C – ( massa C + massa H )
= 528 mg – 240 mg
= 288 mg

nC : nH : nO = massa C : massa H : massa O
ArC : ArH : ArO = 216/12 : 24/1 : 288/16
= 3 : 4 : 3

Rumus Empiris Vitamin C : ( C3 H4 O3 )
Mr Vitamin C = 176
Mr ( C3 H4 O3 )n = 176
( 3 x Ar C + 4 x Ar H + 3 x Ar O )n = 176
( 3 x 12 + 4 x 1 + 3 x 16 )n = 176
( 36 + 4 + 48 )n = 176
88n = 176
n = 176 / 88
n = 2
Rumus Molekulnya : (C3 H4 O3)2 atau C6 H8 O6

Anonim mengatakan...

Diket:
Massa Vitamin C = 528 mg
Massa CO2 = 792 mg
Gr H2O = 216 mg
Mr ( Molekul Relatif ) Vitamin C = 176

Dit:
Cx Hy Oz + O2  CO2 + H2O
528 mg + x  792 mg + 216 mg

Massa C dari CO2 = Ar C / Mr CO2 x massa CO2
= 12 / 44 x 792 mg
= 215,9 mg
= 216 mg

Massa H dari H2O = 2 x Ar H / Mr H2O x massa H2O
= 2 x 1 / 18 x 216
= 1 / 9 x 216
= 23,9 mg
= 24 mg

Massa C + Massa H = 216 mg + 24 mg
= 240 mg
Total massa C + massa H = 216 mg + 24 mg
= 240 mg

Massa O = Massa vitamin C – ( massa C + massa H )
= 528 mg – 240 mg
= 288 mg

nC : nH : nO = massa C : massa H : massa O
ArC : ArH : ArO = 216/12 : 24/1 : 288/16
= 3 : 4 : 3

Rumus Empiris Vitamin C : ( C3 H4 O3 )
Mr Vitamin C = 176
Mr ( C3 H4 O3 )n = 176
( 3 x Ar C + 4 x Ar H + 3 x Ar O )n = 176
( 3 x 12 + 4 x 1 + 3 x 16 )n = 176
( 36 + 4 + 48 )n = 176
88n = 176
n = 176 / 88
n = 2
Rumus Molekulnya : (C3 H4 O3)2 atau C6 H8 O6

Anonim mengatakan...

Diketahui:
Massa Vitamin C = 528 mg
Massa CO2 = 792 mg
Gr H2O = 216 mg
Mr ( Molekul Relatif ) Vitamin C = 176



Jawab:
Cx Hy Oz + O2  CO2 + H2O
528 mg + x  792 mg + 216 mg

Massa C dari CO2 = Ar C / Mr CO2 x massa CO2
= 12 / 44 x 792 mg
= 215,9 mg
= 216 mg

Massa H dari H2O = 2 x Ar H / Mr H2O x massa H2O
= 2 x 1 / 18 x 216
= 1 / 9 x 216
= 23,9 mg
= 24 mg

Massa C + Massa H = 216 mg + 24 mg
= 240 mg
Total massa C + massa H = 216 mg + 24 mg
= 240 mg

Massa O = Massa vitamin C – ( massa C + massa H )
= 528 mg – 240 mg
= 288 mg

nC : nH : nO = massa C : massa H : massa O
ArC : ArH : ArO = 216/12 : 24/1 : 288/16
= 3 : 4 : 3

Rumus Empiris Vitamin C : ( C3 H4 O3 )
Mr Vitamin C = 176
Mr ( C3 H4 O3 )n = 176
( 3 x Ar C + 4 x Ar H + 3 x Ar O )n = 176
( 3 x 12 + 4 x 1 + 3 x 16 )n = 176
( 36 + 4 + 48 )n = 176
88n = 176
n = 176 / 88
n = 2
Rumus Molekulnya : (C3 H4 O3)2 atau C6 H8 O6

Jadi rumus molekulnya (C3 H4 O3)2 atau C6 H8 O6

Nama : Chritine Budianto
Kelas : X-I
Nomor : 11

Ferdinand Kusuma mengatakan...

Diket= gr Vit.C = 528 mgram
gr CO2 = 792 mgram
gr H2O = 216 mgram
Mr Vit.C= 176
Ditanya= RM
D3 [Dijawab] :
CxHyOz + O2 → CO2 + H2O
528mg + X → 792mg + 216mg

Massa C dari CO2 = Ar C / Mr CO2 × Massa CO2
= 12/44 × 792mg
= 215,9mg
= 216mg
massa H dari H2O= 2 . Ar H / Mr H2O × Massa H2O
= 2/18 × 216
= 23,9mg
= 24mg
Massa C + Massa H =
216mg + 24mg = 240mg

Massa O = Massa Vit.C - Massa C + Massa H
= 528mg - 240mg
= 288mg
nC : nH : nO = Massa C : Massa H : Massa O
ArC ArH ArO
= 216/12 : 24/1 : 288/16
= 3:4:3

Rumus Empiris Vitamin C = (C3 H4 O3)n

Mr Vitamin C = 176
Mr (C3H4O3)n = 176
(3.ArC + 4.ArH + 3.ArO)n = 176
(3.12 + 4.1 + 3.16)n = 176
(36+4+48)n = 176
88n = 176
n = 176/88
n = 2

Rumus molekul Vitamin C → (C3H4O3)2 atau C6H8O6

Stevan mengatakan...

Cx Hy + ( x + ¼ y ) O2 x CO2 + ½ y H2O
528 480 792 216

Mol CO2 = 792 : 44 = 18 ( x = 18 )

Mol H2O = 216 : 18 = 12 ( 12 = ½ y )
(24 = y )
C18 H24
= C3H4 ( Rumus Empiris )

[ Cx Hy ] n = 176
[ C3 H4 ] n = 176
[ 12.3 + 1.4 ] n = 176
[ 36 + 4 ] n = 176
40 n = 176
n = 4,4

Rumus Molekul = [ C3H4 ] 4,4
= C13,2 H17,6
= C13 H20
Stevan Mario T

Dendy mengatakan...

Cx Hy + ( x + ¼ y ) O2 x CO2 + ½ y H2O
528 480 792 216

Mol CO2 = 792 : 44 = 18 ( x = 18 )

Mol H2O = 216 : 18 = 12 ( 12 = ½ y )
(24 = y )
C18 H24
= C3H4 ( Rumus Empiris )

[ Cx Hy ] n = 176
[ C3 H4 ] n = 176
[ 12.3 + 1.4 ] n = 176
[ 36 + 4 ] n = 176
40 n = 176
n = 4,4

Rumus Molekul = [ C3H4 ] 4,4
= C13,2 H17,6
= C13 H20

Donatus dendy s

Hendy mengatakan...

Diket:
Massa Vitamin C = 528 mg
Massa CO2 = 792 mg
Gr H2O = 216 mg
Mr ( Molekul Relatif ) Vitamin C = 176

Dit:
Rumus Molekul

Jwb:
Cx Hy Oz + O2 => CO2 + H2O
528 mg + x => 792 mg + 216 mg

Massa C dari CO2 = Ar C / Mr CO2 x massa CO2
= 12 / 44 x 792 mg
= 215,9 mg
= 216 mg

Massa H dari H2O = 2 x Ar H / Mr H2O x massa H2O
= 2 x 1 / 18 x 216
= 1 / 9 x 216
= 23,9 mg
= 24 mg

Massa C + Massa H = 216 mg + 24 mg
= 240 mg
Total massa C + massa H = 216 mg + 24 mg
= 240 mg

Massa O = Massa vitamin C – ( massa C + massa H )
= 528 mg – 240 mg
= 288 mg

nC : nH : nO = massa C : massa H : massa O
ArC : ArH : ArO = 216/12 : 24/1 : 288/16
= 3 : 4 : 3

Rumus Empiris Vitamin C : ( C3 H4 O3 )
Mr Vitamin C = 176
Mr ( C3 H4 O3 )n = 176
( 3 x Ar C + 4 x Ar H + 3 x Ar O )n = 176
( 3 x 12 + 4 x 1 + 3 x 16 )n = 176
( 36 + 4 + 48 )n = 176
88n = 176
n = 176 / 88
n = 2
Rumus Molekulnya : (C3 H4 O3)2 atau C6 H8 O6