CxHyOz + O2 = CO2 + H2O 528mg 792mg 216mgKadar c = 12/44 x 216 = 216mgKadar H = 2 x 1/18 = 24mgKadar O = 528 - (216-24) = 288C : H : O = 216/12 : 24/1 : 288/16 = 18 : 24 : 18 = 3 : 4 : 3RE = C3H4O3RM(CxHyOz)n = MR(C3H4O3)n = 176{(3x12)+(1x4)+(3x16)}n = 176(36+4+48)n = 176 88n = 176 n = 176/88 = 2RM = (C3H4O3)2 = C6H8O6
Nama : Abednego LoekitoNomor : 1Kelas : X-1Bidang Studi : KimiaTanggal : 11 April 2008Ulangan ke : REMIDI Latihan 4.3Semester : IISebanyak 528 mg vitamin C dibakar sempurna menghasilkan 792 mg CO2 dan 216 mg H2O. Jika MR vitamin C sebesar 176, tentukan rumus molekulnya!Jawab :CxHyOz + O2 = CO2 + H2O528 mg 480 mg 792 mg 216 mgKadar C = 12 / 44 x 216 = 216 mgKadar H = 1 / 18 x 2= 24 mgKadar O = massa CxHyOz – (massa C + massa H)= 528 - (216 + 24)= 288 mgPerbandingan molekul C : H : O = 216 / 12 : 24 / 1 : 288 / 16= 18 : 24 : 18= 3 : 4 : 3Rumus Empiris = C3H4O3Rumus Molekul[CxHyOz]n = MR[C3H4O3]n = 176[(3 x 12) + (1 x 4) + (3 x 16)]n = 176[36 + 4 + 48]n = 17688n = 176n = 176 / 88 = 2Rumus Molekul : [C3H4O3]2 = C6H8O6Jadi rumus molekul vitamin C tersebut adalah C6H8O6
jawab.. C : H : O =216/12 : 24/1 : 288/16 = 18 : 24 : 18 = 3 : 4 : 3 =Rumus Empiris C3H4O3Rumus Mol(CxHyOz)n=MR (C3H4O3)n=176 ((12x3)+(1x4)+(16x3))n=176 (36+4+48)n=176 88n=176 n=176/88 n=2 Jadi Rumus Molekul nya :(C3H4O3)2 : C6H8O6 ====== * gaby *
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CxHyOz + O2 = CO2 + H2O
528mg 792mg 216mg
Kadar c = 12/44 x 216
= 216mg
Kadar H = 2 x 1/18
= 24mg
Kadar O = 528 - (216-24)
= 288
C : H : O = 216/12 : 24/1 : 288/16
= 18 : 24 : 18
= 3 : 4 : 3
RE = C3H4O3
RM
(CxHyOz)n = MR
(C3H4O3)n = 176
{(3x12)+(1x4)+(3x16)}n = 176
(36+4+48)n = 176
88n = 176
n = 176/88
= 2
RM = (C3H4O3)2
= C6H8O6
Nama : Abednego Loekito
Nomor : 1
Kelas : X-1
Bidang Studi : Kimia
Tanggal : 11 April 2008
Ulangan ke : REMIDI Latihan 4.3
Semester : II
Sebanyak 528 mg vitamin C dibakar sempurna menghasilkan 792 mg CO2 dan 216 mg H2O. Jika MR vitamin C sebesar 176, tentukan rumus molekulnya!
Jawab :
CxHyOz + O2 = CO2 + H2O
528 mg 480 mg 792 mg 216 mg
Kadar C = 12 / 44 x 216
= 216 mg
Kadar H = 1 / 18 x 2
= 24 mg
Kadar O = massa CxHyOz – (massa C + massa H)
= 528 - (216 + 24)
= 288 mg
Perbandingan molekul
C : H : O = 216 / 12 : 24 / 1 : 288 / 16
= 18 : 24 : 18
= 3 : 4 : 3
Rumus Empiris = C3H4O3
Rumus Molekul
[CxHyOz]n = MR
[C3H4O3]n = 176
[(3 x 12) + (1 x 4) + (3 x 16)]n = 176
[36 + 4 + 48]n = 176
88n = 176
n = 176 / 88 = 2
Rumus Molekul :
[C3H4O3]2 = C6H8O6
Jadi rumus molekul vitamin C tersebut adalah C6H8O6
jawab..
C : H : O =
216/12 : 24/1 : 288/16 =
18 : 24 : 18 =
3 : 4 : 3 =
Rumus Empiris C3H4O3
Rumus Mol(CxHyOz)n=MR
(C3H4O3)n=176
((12x3)+(1x4)+(16x3))n=176
(36+4+48)n=176
88n=176
n=176/88
n=2
Jadi Rumus Molekul nya :(C3H4O3)2
: C6H8O6
======
* gaby *
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