Rabu, 03 September 2008

REMIDI UL. KD 1 (STRUKTUR ATOM, S. PERIODIK)

1. Unsur Litium (Li) terdiri atas dua isotop Yaiut Li-6 dan Li-7. Jika massa rata-
rata = 9,941sma, massa Li-6 dan Li-7 dianggap sama dengan nomor massa, tentukan
kelimpahan masing-masing isotop Li di alam !

2. Talium (Tl) terdiri atas dua isotop Tl-203 dan Tl-205. Jika kelimpahan masing-
masing 29,52% dan 70,48%, tentukan massa rata-ratanya!
Diposting oleh di
Label: ,

60 komentar:

Unknown mengatakan...

1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9

9 September 2008 pukul 16.22
Unknown mengatakan...

Lanjutan no 1..
9,941=13,878N%
N%= 9,941:13,878
=0,72

2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096

Elisabeth Fitria Mega Anggraeni
X-3/13

9 September 2008 pukul 16.30
Natasya Intan mengatakan...

Nama : Natasya Intan P
Kls/No: x-1/29

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72

9 September 2008 pukul 17.21
Natasya Intan mengatakan...

Nama : Natasya Intan P
kls/No: x-1/29

Lanjutan Komentar sebelumnya...

2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

9 September 2008 pukul 17.25
Sandjojo mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

Stefanus sandjojo
X-4/32

9 September 2008 pukul 20.24
adichandraW mengatakan...

nama:adi chandra wijaya
Kls/no:x-1/1

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096


2008 September 10 16:48

10 September 2008 pukul 17.17
Unknown mengatakan...
Komentar ini telah dihapus oleh pengarang.
11 September 2008 pukul 14.24
Unknown mengatakan...

1. Diketahui =
Massa rata2=9,941 sma
massa Li-6 massa Li-7= 6,939

Ditanya =
kelimpahan masing2 isotop

Jawab =
Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7

jika nomor massa sama, kelimpahan masing2 isotop juga sama.

n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72



2. Diketahui:
TL-203=29,52%
TL-205=70,48%

Ditanya: Massa rata

Jawab:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096


NAMA : NATASYA ANGELINE
KELAS : X-4/ 25

11 September 2008 pukul 14.25
Vbee mengatakan...

1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939

Ditanya : % kelimpahan ke2 isotop

Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7

Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.

~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"


2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%

Ditanya: Massa rata**nya

Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%

5992,56+14448,4
= _________________
100%

20440,96
= ________
100%

= "204,4096"
By :feby Roselin R X-4/10

11 September 2008 pukul 16.28
Raditya Marnugroho mengatakan...

nama : Raditya Marnugroho Limas
Kls/no:x-1/31

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

11 September 2008 pukul 17.44
targa mengatakan...

nama:targa santoso putra
Kls/no:x-1/36

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

11 September 2008 pukul 17.49
Okka mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096
Okka X-4/28

11 September 2008 pukul 19.55
BeaTRiCe aMaNDa mengatakan...

1.
Dik: Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939Dit: persen kelimpahan ke2 isotop
jwb: ar rata2 = (Ar 1xp%)+(Ar2 xq%)
Ar1 = massa Li-6 = 6,939
p% = persen kelimpahan Li-6
Ar2 = massa Li-7 =6,939
q% = persen kelimpahan Li-7
krn no massanya sama, maka
kelimpahan ke2 isotop sama:
n% = persen kelimpahan ke2
isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72

2.
Dik: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya
Jwb:
= 29,52%.203+70,48.205
____________________
29,52%+70,48%


= 5992,56+14448,4
_______________
100%


= 20440,96
________
100%


= 204,4096



Beatrice Amanda A.
X-1 / 05

12 September 2008 pukul 14.16
Kevhin mengatakan...

Kevin Aditya Kusgianto x-4/19

1.Diketahui: Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939Dit: persen kelimpahan ke2 isotop
jawab: ar rata2 = (Ar 1xp%)+(Ar2 xq%)
Ar1 = massa Li-6 = 6,939
p% = persen kelimpahan Li-6
Ar2 = massa Li-7 =6,939
q% = persen kelimpahan Li-7
karena no massanya sama, maka
kelimpahan ke2 isotop sama:
n% = persen kelimpahan ke2
isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72

2.Diketahui: TL-203=29,52%
TL-205=70,48%
Ditanyakan: Massa rata-ratanya
Jawab:
= 29,52%.203+70,48.205
____________________
29,52%+70,48%


= 5992,56+14448,4
_______________
100%


= 20440,96
________
100%


= 204,4096

12 September 2008 pukul 14.58
denica mengatakan...

Denica mengatakan bahwa:

1. dkt : Ar rata-rata=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya :Brp persen kelimpahan 2 isotopnya=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn nomor massa sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Dkt: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata- ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4

Denica X-4/15

12 September 2008 pukul 15.13
Stevie X-3/37 mengatakan...

Stevie Pramudita D
X-3/37

1. Diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939

Dit : Persen(%) kelimpahan ke2 isotop=?

Jwb : Ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n% = persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
Jadi : persen kelimpahan kedua isotop = 0,72%


2.Diket: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096
Jadi : masa rata-ratanya = 204,4096

12 September 2008 pukul 16.04
JOVi mengatakan...

Ezra berkata..
1. dkt : Ar rata-rata=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya :Brp persen kelimpahan 2 isotopnya=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn nomor massa sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Dkt: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata- ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4

Ezra X-4/9

12 September 2008 pukul 16.42
JOVi mengatakan...

Ezra berkata..
1. dkt : Ar rata-rata=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya :Brp persen kelimpahan 2 isotopnya=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn nomor massa sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Dkt: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata- ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4

Ezra X-4/9

12 September 2008 pukul 16.42
JOVi mengatakan...

Nama : JOVI
Kls/No: x-1/22

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72

2008 September 9 17:21
Blogger JOVi berkata...

Nama :JOVI
kls/No: x-1/22

Lanjutan Komentar sebelumnya...

2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

2008 September 9 17:25

12 September 2008 pukul 16.46
JOVi mengatakan...

Nama : JOVI
Kls/No: x-1/22

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72

2008 September 9 17:21
Blogger JOVi berkata...

Nama :JOVI
kls/No: x-1/22

Lanjutan Komentar sebelumnya...

2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

2008 September 9 17:25

12 September 2008 pukul 16.52
GrAcE mengatakan...

NAMA = Grace Samantha S
kelas = x-1
No.Abs = 19

1.
DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7

Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72

2.
Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%

= 5992,56+14448,4
-----------------
100%

= 20440,96
------------
100%

= 204,4096

12 September 2008 pukul 18.56
Anastasia Devina mengatakan...

1. Diket : Ar rata*= 9,941 sma
massa Li-6=Li-7=6,939
Sit: % kelimpahan isotop
jwb: Ar rata*=(Ar1xp%)+(Ar2xq%)
*Ar1= massa Li-6= 6,939
*p%= persen kelimpahan Li-6
Ar2= massa Li-7= 6,939
*q%= persen kelimpahan Li-7
krn nomor massa sama, maka % kelimpahan 2 isotop juga sama.
n%= persen kelimpahan ke-2 isoyop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%= 9,941 :13,878
=0,72

2. Diket:Tl-203= 29,52%
Tl-205= 70,48%
Dit : massa rata*
Jwb:
= 29,52%.203+70,48%.205
______________________
29,52%+70,48%
= 5992,56+14448,4
________________
100%
= 20440,96
___________
100%
= 204,4096

Nama: Anastasia Devina S
Kelas: X-3/02

12 September 2008 pukul 20.25
Meggie X-3 mengatakan...

1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9
9,941=13,878N%
N%= 9,941:13,878
=0,72

2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096

2. 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096

13 September 2008 pukul 11.31
*Gabriella Nerina* mengatakan...

Nama:Gabriella Nerina S.
Kelas:X-4/12
1. Diket:Ar rata2=9,941 sma
Massa Li-6=massa Li-7=6,939
Ditanya:Persen kelimpahan kedua isotop..?
Jawab:Ar rata2=(Ar1.P%)+(Ar2.Q%)
*Ar1=Massa Li-6=6,939
*P%=Persen kelimpahan Li-6
*Ar2=massa Li-7=6,939
*q%=persen kelimpahan Li-7

Apabila no.massanya sama,maka persen kelimpahan kedua isotop juga sama

N%=Persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%=9,941 : 13,878
n%=0,72

13 September 2008 pukul 11.37
*Gabriella Nerina* mengatakan...

2. Diket:TL-203=29,52%
TL-205=70,48%
Dit:Massa rata2..?
Jawab:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%

= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

13 September 2008 pukul 11.42
markus mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72

2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096

markus agung santoso yani x-4/23

13 September 2008 pukul 12.19
kelvin Wijaya-x-4-18 mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

Kelvin wijaya x-4 / 18

13 September 2008 pukul 12.27
Yovita mengatakan...
Komentar ini telah dihapus oleh pengarang.
13 September 2008 pukul 13.23
Yovita mengatakan...

1.Dik: Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Dit: persen kelimpahan ke2 isotop
jwb: ar rata2 = (Ar 1xp%)+(Ar2 xq%)
Ar1 = massa Li-6 = 6,939
p% = persen kelimpahan Li-6
Ar2 = massa Li-7 =6,939
q% = persen kelimpahan Li-7
krn no massanya sama, maka
kelimpahan ke2 isotop sama:
n% = persen kelimpahan ke2
isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72

2.
Dik: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya
Jwb:
= 29,52%.203+70,48.205
____________________
29,52%+70,48%


= 5992,56+14448,4
_______________
100%


= 20440,96
________
100%


= 204,4096

Nama : Yovita Liana Dewi
Kelas : X-3 / 42

13 September 2008 pukul 13.30
henry j mengatakan...

Nama: henry j
Kelas:x3-19
1. Diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939

Dit : Persen(%) kelimpahan ke2 isotop=?

Jwb : Ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n% = persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
Jadi : persen kelimpahan kedua isotop = 0,72%


2.Diket: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096
Jadi : masa rata-ratanya = 204,4096

13 September 2008 pukul 15.09
william mengatakan...

nama:william hermantara
Kls/no:x-4/38

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

13 September 2008 pukul 17.12
Nela mengatakan...
Komentar ini telah dihapus oleh pengarang.
13 September 2008 pukul 18.06
Nela mengatakan...

1. Diket : Ar rata*= 9,941 sma
massa Li-6=Li-7=6,939
Sit: % kelimpahan isotop
jwb: Ar rata*=(Ar1xp%)+(Ar2xq%)
*Ar1= massa Li-6= 6,939
*p%= persen kelimpahan Li-6
Ar2= massa Li-7= 6,939
*q%= persen kelimpahan Li-7
krn nomor massa sama, maka % kelimpahan 2 isotop juga sama.
n%= persen kelimpahan ke-2 isoyop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%= 9,941 :13,878
=0,72

2. Diket:Tl-203= 29,52%
Tl-205= 70,48%
Dit : massa rata*
Jwb:
= 29,52%.203+70,48%.205
______________________
29,52%+70,48%
= 5992,56+14448,4
________________
100%
= 20440,96
___________
100%
= 204,4096



Nela Puspitasari
X.3/34

13 September 2008 pukul 18.07
nessa mengatakan...

1.
DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7

Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72

2.
Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%

= 5992,56+14448,4
-----------------
100%

= 20440,96
------------
100%

= 204,4096

14 September 2008 pukul 20.38
nessa mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

14 September 2008 pukul 20.40
valen mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

14 September 2008 pukul 20.45
valen mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

14 September 2008 pukul 20.45
yelsi kristafel mengatakan...

1>Ar rata2= (Ar1.p%)+(Ar2.q%)
Ar1=massa Li-6=6,939
p%=persen kelimpahan Li-6
Ar2=massa Li-7=6,939
q%=persen kelimpahan Li-7
karena no.massa sama maka kelimpahan kedua isotop sama.
n%=persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n=0,72%

2>Ar=29,5*203+ 70,48*205
______________________
29,52+70,48
= 5988,5+14448,4
________________
100
= 20436,9
_______
100
= 204,4

15 September 2008 pukul 15.21
Anastacia Ganis X-4 mengatakan...

1> Dik: Ar rata2:9,941sma
Massa Li-6 dan Li-7=6,939
Dit: % kelimpahan 2 isotop itu
Jwb: Ar rata2=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= % kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= % kelimpahan Li-7
Kelimpahan 2 isotop sama karena nmr massanya sama
N%= % kelimpahan 2 isotop
9,941= (6,939N%)+(6,939N%)
9,941=13,878N%
N%= 9,941:13,878
N%= 0,72


2> Dik: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata2
Jwb: =29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100%
=204,4096

15 September 2008 pukul 15.43
Unknown mengatakan...

1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9

Lanjutan no 1..
9,941=13,878N%
N%= 9,941:13,878
=0,72

2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096

Hendrika Beatrix A.N
X-1/20

15 September 2008 pukul 16.24
Unknown mengatakan...

1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9

9,941=13,878N%
N%= 9,941:13,878
=0,72

2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100%
=204,4096

Nuri Arintha
x-1 / 30

15 September 2008 pukul 16.41
Unknown mengatakan...

NAMA : Michelle Delovita Ersica
kelas : x-1
No.Abs : 28

1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7

Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72

2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%

= 5992,56+14448,4
-----------------
100%

= 20440,96
------------
100%

= 204,4096

15 September 2008 pukul 20.27
Yenie mengatakan...
Komentar ini telah dihapus oleh pengarang.
17 September 2008 pukul 08.52
Yenie mengatakan...

1.diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7

Krn nomor massanya sm,maka persen kelimpahan kedua isoytop juga sama.

n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72

2. diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%

5992,56 + 14448,4
= ______________________
100%

20440,96
=___________
100%

=204,4096

Yenie Widjojo
X-1 / 39

17 September 2008 pukul 08.57
ardhe leonardo mengatakan...

ardhe leonardo
X-1/04
1.diketahui: Ar rata2=9,941sma massa Li-6=massa Li-7=6,939
tanya: persen kelimpahan ke2 isotop?
jawab: Ar rata2=(Ar1.p%)+Ar2.q%)
Ar1=massa Li-6=6,939
p%=persen kelimpahan Li-6
Ar2=massa Li-7=6,939
q%=persen kelimpahan Li-7
krn nomor massanya sama, maka persen kelimpahan ke 2 isotopnya sama
n%=persen kelimpahan ke 2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%=9,941:13,878
n%=0,72
jadi persen ke 2 isotop adalah 0,72%

2. diketahui:TL-203=29,52%
TL-205=70,48%
tanya: massa rata2nya?
jawab:
=(29,52%.203)+(70,48%.205)
____________________________
29,52%+70,48%
=5992,56+14448,4
_________________
100%
=20440,96
_________
100%
Ar = 204,4096 sma
jadi rata2nya adalah 204,4096sma

17 September 2008 pukul 20.28
Gaby mengatakan...

1.
Dik:
Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit :
persen kelimpahan kedua isotop
Jwb:
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7

Karena nomor massanya sama,maka persen kelimpahan kedua isotop juga sama.
n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72

2.
Dik:
TL-203=29,52% TL-205=70,48%
Dit : massa rata-rata nya
Jwb:
29,52%.203+70,48%.205
= ______________________
29,52% + 70,48%

5992,56 + 14448,4
= _________________
100%

20440,96
=__________
100%

=204,4096

Gabriella Valentina E
X-1 / 15

18 September 2008 pukul 18.38
andreas mengatakan...

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096





andreas ardy d
x-2 / 3

18 September 2008 pukul 21.03
Unknown mengatakan...

NAMA : elsa paulina tjipto
kelas : x-1
No.Abs : 11

1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7

Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72

2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%

= 5992,56+14448,4
-----------------
100%

= 20440,96
------------
100%

= 204,4096

20 September 2008 pukul 12.33
Inggrid mengatakan...

1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939

Ditanya : % kelimpahan ke2 isotop

Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7

Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.

~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"


2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%

Ditanya: Massa rata**nya

Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%

5992,56+14448,4
= _________________
100%

20440,96
= ________
100%

= "204,4096"
Inggrid Kristiadi X 4 ? 17

21 September 2008 pukul 09.50
Inggrid mengatakan...

1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939

Ditanya : % kelimpahan ke2 isotop

Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7

Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.

~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"


2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%

Ditanya: Massa rata**nya

Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%

5992,56+14448,4
= _________________
100%

20440,96
= ________
100%

= "204,4096"
Inggrid Kristiadi X 4 / 17

21 September 2008 pukul 09.51
gloria y.p mengatakan...

Nama: Gloria Y.P
Kls/No :x-1/18

1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
Lanjutan Komentar sebelumnya...

2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

23 September 2008 pukul 15.58
Unknown mengatakan...

. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9

Lanjutan no 1..
9,941=13,878N%
N%= 9,941:13,878
=0,72

2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096

laurensia karina astriani
X-1/24

24 September 2008 pukul 14.58
Priza mengatakan...

1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939

Ditanya : % kelimpahan ke2 isotop

Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7

Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.

~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"


2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%

Ditanya: Massa rata**nya

Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%

5992,56+14448,4
= _________________
100%

20440,96
= ________
100%

= "204,4096"

By:Prissa Anita A
X-2/33

24 September 2008 pukul 16.10
Sasa mengatakan...

1.
Diketahui :

Ar rata2=9,941 sma

massa Li-6=massa Li-7=6,939

tanya : persen kelimpahan ke2 isotop=?

jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)

*Ar1 = massa Li-6=6,939

*p% =persen kelimpahan Li-6

*Ar2 = massa Li-7 =6,939

*q% =persen kelimpahan Li-7

karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama:

n%=persen kelimpahan kedua isotop

9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72


2.
Jawab:

= 29,52%.203+70,48.205
__________________________
29,52%+70,48%


= 5992,56+14448,4
____________________
100%

= 20440,96
_____________
100%

= 204,4096

25 September 2008 pukul 14.59
marlene g.i X/2 mengatakan...

1. dik: Ar rt2= 9,941 sma
Li-6= Li-7 =6,939
dit: %klimphn ke-2 isotop
jwb: Ar rt2=(Ar1.p%)+(Ar2.9%)
Ar1= massa Li-6=6,939
p% = %klimphn Li-6
Ar2= massa Li-7=6,939
9% = %klimphn Li-7
klimphn 2 isotop sm krn no. massanya sm.
N% = %klimphn ke-2 isotop
9,941= (6,939N%)+(6,939N%)
9,941= 13,878N%
N% = 0,72

2. dik: TL-203=29,52%
TL-205=70,48%
DIT: msa rt2
jwb: 29,52%.203 + 70,48.205
______________________
29,52% + 70,48%
= 5992,56 + 14448,4
______________________
100%
= 20,4096
_________
100%
=204,4096

marlene g.i x-2

4 Oktober 2008 pukul 20.31
Anita Nathania mengatakan...

Isabella Lupita
X-2/21

1.Diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7

Karena nomor massanya sama,maka persen kelimpahan kedua isoytop juga sama.a

n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72

2. Diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%

5992,56 + 14448,4
= ______________________
100%

20440,96
=___________
100%

=204,4096

10 Oktober 2008 pukul 20.31
Anita Nathania mengatakan...

Jasmine Hutama G.
X-2/21

1.Diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7

Karena nomor massanya sama,maka persen kelimpahan kedua isoytop juga sama.a

n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72

2. Diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%

5992,56 + 14448,4
= ______________________
100%

20440,96
=___________
100%

=204,4096

10 Oktober 2008 pukul 20.45
Anita Nathania mengatakan...

Jasmine Hutama G.
X-2/21

1.Diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7

Karena nomor massanya sama,maka persen kelimpahan kedua isoytop juga sama.a

n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72

2. Diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%

5992,56 + 14448,4
= ______________________
100%

20440,96
=___________
100%

=204,4096

10 Oktober 2008 pukul 20.45
bora mengatakan...

1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7

Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72

2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%

= 5992,56+14448,4
-----------------
100%

= 20440,96
------------
100%

= 204,4096

20 Oktober 2008 pukul 20.40
bora mengatakan...

1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7

Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72

2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%

= 5992,56+14448,4
-----------------
100%

= 20440,96
------------
100%

= 204,4096

20 Oktober 2008 pukul 20.40

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