1. Unsur Litium (Li) terdiri atas dua isotop Yaiut Li-6 dan Li-7. Jika massa rata-
rata = 9,941sma, massa Li-6 dan Li-7 dianggap sama dengan nomor massa, tentukan
kelimpahan masing-masing isotop Li di alam !
2. Talium (Tl) terdiri atas dua isotop Tl-203 dan Tl-205. Jika kelimpahan masing-
masing 29,52% dan 70,48%, tentukan massa rata-ratanya!
Rabu, 03 September 2008
REMIDI UL. KD 1 (STRUKTUR ATOM, S. PERIODIK)
Langganan:
Posting Komentar (Atom)
60 komentar:
1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9
Lanjutan no 1..
9,941=13,878N%
N%= 9,941:13,878
=0,72
2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096
Elisabeth Fitria Mega Anggraeni
X-3/13
Nama : Natasya Intan P
Kls/No: x-1/29
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
Nama : Natasya Intan P
kls/No: x-1/29
Lanjutan Komentar sebelumnya...
2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
Stefanus sandjojo
X-4/32
nama:adi chandra wijaya
Kls/no:x-1/1
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
2008 September 10 16:48
1. Diketahui =
Massa rata2=9,941 sma
massa Li-6 massa Li-7= 6,939
Ditanya =
kelimpahan masing2 isotop
Jawab =
Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
jika nomor massa sama, kelimpahan masing2 isotop juga sama.
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2. Diketahui:
TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata
Jawab:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
NAMA : NATASYA ANGELINE
KELAS : X-4/ 25
1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939
Ditanya : % kelimpahan ke2 isotop
Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7
Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.
~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"
2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%
Ditanya: Massa rata**nya
Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%
5992,56+14448,4
= _________________
100%
20440,96
= ________
100%
= "204,4096"
By :feby Roselin R X-4/10
nama : Raditya Marnugroho Limas
Kls/no:x-1/31
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
nama:targa santoso putra
Kls/no:x-1/36
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
Okka X-4/28
1.
Dik: Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939Dit: persen kelimpahan ke2 isotop
jwb: ar rata2 = (Ar 1xp%)+(Ar2 xq%)
Ar1 = massa Li-6 = 6,939
p% = persen kelimpahan Li-6
Ar2 = massa Li-7 =6,939
q% = persen kelimpahan Li-7
krn no massanya sama, maka
kelimpahan ke2 isotop sama:
n% = persen kelimpahan ke2
isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.
Dik: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya
Jwb:
= 29,52%.203+70,48.205
____________________
29,52%+70,48%
= 5992,56+14448,4
_______________
100%
= 20440,96
________
100%
= 204,4096
Beatrice Amanda A.
X-1 / 05
Kevin Aditya Kusgianto x-4/19
1.Diketahui: Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939Dit: persen kelimpahan ke2 isotop
jawab: ar rata2 = (Ar 1xp%)+(Ar2 xq%)
Ar1 = massa Li-6 = 6,939
p% = persen kelimpahan Li-6
Ar2 = massa Li-7 =6,939
q% = persen kelimpahan Li-7
karena no massanya sama, maka
kelimpahan ke2 isotop sama:
n% = persen kelimpahan ke2
isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diketahui: TL-203=29,52%
TL-205=70,48%
Ditanyakan: Massa rata-ratanya
Jawab:
= 29,52%.203+70,48.205
____________________
29,52%+70,48%
= 5992,56+14448,4
_______________
100%
= 20440,96
________
100%
= 204,4096
Denica mengatakan bahwa:
1. dkt : Ar rata-rata=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya :Brp persen kelimpahan 2 isotopnya=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn nomor massa sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Dkt: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata- ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4
Denica X-4/15
Stevie Pramudita D
X-3/37
1. Diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Dit : Persen(%) kelimpahan ke2 isotop=?
Jwb : Ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n% = persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
Jadi : persen kelimpahan kedua isotop = 0,72%
2.Diket: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
Jadi : masa rata-ratanya = 204,4096
Ezra berkata..
1. dkt : Ar rata-rata=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya :Brp persen kelimpahan 2 isotopnya=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn nomor massa sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Dkt: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata- ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4
Ezra X-4/9
Ezra berkata..
1. dkt : Ar rata-rata=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya :Brp persen kelimpahan 2 isotopnya=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn nomor massa sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Dkt: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata- ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4
Ezra X-4/9
Nama : JOVI
Kls/No: x-1/22
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2008 September 9 17:21
Blogger JOVi berkata...
Nama :JOVI
kls/No: x-1/22
Lanjutan Komentar sebelumnya...
2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
2008 September 9 17:25
Nama : JOVI
Kls/No: x-1/22
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2008 September 9 17:21
Blogger JOVi berkata...
Nama :JOVI
kls/No: x-1/22
Lanjutan Komentar sebelumnya...
2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
2008 September 9 17:25
NAMA = Grace Samantha S
kelas = x-1
No.Abs = 19
1.
DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7
Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72
2.
Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%
= 5992,56+14448,4
-----------------
100%
= 20440,96
------------
100%
= 204,4096
1. Diket : Ar rata*= 9,941 sma
massa Li-6=Li-7=6,939
Sit: % kelimpahan isotop
jwb: Ar rata*=(Ar1xp%)+(Ar2xq%)
*Ar1= massa Li-6= 6,939
*p%= persen kelimpahan Li-6
Ar2= massa Li-7= 6,939
*q%= persen kelimpahan Li-7
krn nomor massa sama, maka % kelimpahan 2 isotop juga sama.
n%= persen kelimpahan ke-2 isoyop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%= 9,941 :13,878
=0,72
2. Diket:Tl-203= 29,52%
Tl-205= 70,48%
Dit : massa rata*
Jwb:
= 29,52%.203+70,48%.205
______________________
29,52%+70,48%
= 5992,56+14448,4
________________
100%
= 20440,96
___________
100%
= 204,4096
Nama: Anastasia Devina S
Kelas: X-3/02
1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9
9,941=13,878N%
N%= 9,941:13,878
=0,72
2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096
2. 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096
Nama:Gabriella Nerina S.
Kelas:X-4/12
1. Diket:Ar rata2=9,941 sma
Massa Li-6=massa Li-7=6,939
Ditanya:Persen kelimpahan kedua isotop..?
Jawab:Ar rata2=(Ar1.P%)+(Ar2.Q%)
*Ar1=Massa Li-6=6,939
*P%=Persen kelimpahan Li-6
*Ar2=massa Li-7=6,939
*q%=persen kelimpahan Li-7
Apabila no.massanya sama,maka persen kelimpahan kedua isotop juga sama
N%=Persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%=9,941 : 13,878
n%=0,72
2. Diket:TL-203=29,52%
TL-205=70,48%
Dit:Massa rata2..?
Jawab:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096
markus agung santoso yani x-4/23
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
Kelvin wijaya x-4 / 18
1.Dik: Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Dit: persen kelimpahan ke2 isotop
jwb: ar rata2 = (Ar 1xp%)+(Ar2 xq%)
Ar1 = massa Li-6 = 6,939
p% = persen kelimpahan Li-6
Ar2 = massa Li-7 =6,939
q% = persen kelimpahan Li-7
krn no massanya sama, maka
kelimpahan ke2 isotop sama:
n% = persen kelimpahan ke2
isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.
Dik: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya
Jwb:
= 29,52%.203+70,48.205
____________________
29,52%+70,48%
= 5992,56+14448,4
_______________
100%
= 20440,96
________
100%
= 204,4096
Nama : Yovita Liana Dewi
Kelas : X-3 / 42
Nama: henry j
Kelas:x3-19
1. Diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Dit : Persen(%) kelimpahan ke2 isotop=?
Jwb : Ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n% = persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
Jadi : persen kelimpahan kedua isotop = 0,72%
2.Diket: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata-ratanya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
Jadi : masa rata-ratanya = 204,4096
nama:william hermantara
Kls/no:x-4/38
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1. Diket : Ar rata*= 9,941 sma
massa Li-6=Li-7=6,939
Sit: % kelimpahan isotop
jwb: Ar rata*=(Ar1xp%)+(Ar2xq%)
*Ar1= massa Li-6= 6,939
*p%= persen kelimpahan Li-6
Ar2= massa Li-7= 6,939
*q%= persen kelimpahan Li-7
krn nomor massa sama, maka % kelimpahan 2 isotop juga sama.
n%= persen kelimpahan ke-2 isoyop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%= 9,941 :13,878
=0,72
2. Diket:Tl-203= 29,52%
Tl-205= 70,48%
Dit : massa rata*
Jwb:
= 29,52%.203+70,48%.205
______________________
29,52%+70,48%
= 5992,56+14448,4
________________
100%
= 20440,96
___________
100%
= 204,4096
Nela Puspitasari
X.3/34
1.
DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7
Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72
2.
Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%
= 5992,56+14448,4
-----------------
100%
= 20440,96
------------
100%
= 204,4096
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1>Ar rata2= (Ar1.p%)+(Ar2.q%)
Ar1=massa Li-6=6,939
p%=persen kelimpahan Li-6
Ar2=massa Li-7=6,939
q%=persen kelimpahan Li-7
karena no.massa sama maka kelimpahan kedua isotop sama.
n%=persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n=0,72%
2>Ar=29,5*203+ 70,48*205
______________________
29,52+70,48
= 5988,5+14448,4
________________
100
= 20436,9
_______
100
= 204,4
1> Dik: Ar rata2:9,941sma
Massa Li-6 dan Li-7=6,939
Dit: % kelimpahan 2 isotop itu
Jwb: Ar rata2=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= % kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= % kelimpahan Li-7
Kelimpahan 2 isotop sama karena nmr massanya sama
N%= % kelimpahan 2 isotop
9,941= (6,939N%)+(6,939N%)
9,941=13,878N%
N%= 9,941:13,878
N%= 0,72
2> Dik: TL-203=29,52%
TL-205=70,48%
Dit: Massa rata2
Jwb: =29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100%
=204,4096
1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9
Lanjutan no 1..
9,941=13,878N%
N%= 9,941:13,878
=0,72
2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096
Hendrika Beatrix A.N
X-1/20
1. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9
9,941=13,878N%
N%= 9,941:13,878
=0,72
2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100%
=204,4096
Nuri Arintha
x-1 / 30
NAMA : Michelle Delovita Ersica
kelas : x-1
No.Abs : 28
1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7
Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72
2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%
= 5992,56+14448,4
-----------------
100%
= 20440,96
------------
100%
= 204,4096
1.diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7
Krn nomor massanya sm,maka persen kelimpahan kedua isoytop juga sama.
n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72
2. diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%
5992,56 + 14448,4
= ______________________
100%
20440,96
=___________
100%
=204,4096
Yenie Widjojo
X-1 / 39
ardhe leonardo
X-1/04
1.diketahui: Ar rata2=9,941sma massa Li-6=massa Li-7=6,939
tanya: persen kelimpahan ke2 isotop?
jawab: Ar rata2=(Ar1.p%)+Ar2.q%)
Ar1=massa Li-6=6,939
p%=persen kelimpahan Li-6
Ar2=massa Li-7=6,939
q%=persen kelimpahan Li-7
krn nomor massanya sama, maka persen kelimpahan ke 2 isotopnya sama
n%=persen kelimpahan ke 2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n%=9,941:13,878
n%=0,72
jadi persen ke 2 isotop adalah 0,72%
2. diketahui:TL-203=29,52%
TL-205=70,48%
tanya: massa rata2nya?
jawab:
=(29,52%.203)+(70,48%.205)
____________________________
29,52%+70,48%
=5992,56+14448,4
_________________
100%
=20440,96
_________
100%
Ar = 204,4096 sma
jadi rata2nya adalah 204,4096sma
1.
Dik:
Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit :
persen kelimpahan kedua isotop
Jwb:
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7
Karena nomor massanya sama,maka persen kelimpahan kedua isotop juga sama.
n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72
2.
Dik:
TL-203=29,52% TL-205=70,48%
Dit : massa rata-rata nya
Jwb:
29,52%.203+70,48%.205
= ______________________
29,52% + 70,48%
5992,56 + 14448,4
= _________________
100%
20440,96
=__________
100%
=204,4096
Gabriella Valentina E
X-1 / 15
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
Ditanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no massanya sama,maka %kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
andreas ardy d
x-2 / 3
NAMA : elsa paulina tjipto
kelas : x-1
No.Abs : 11
1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7
Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72
2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%
= 5992,56+14448,4
-----------------
100%
= 20440,96
------------
100%
= 204,4096
1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939
Ditanya : % kelimpahan ke2 isotop
Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7
Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.
~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"
2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%
Ditanya: Massa rata**nya
Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%
5992,56+14448,4
= _________________
100%
20440,96
= ________
100%
= "204,4096"
Inggrid Kristiadi X 4 ? 17
1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939
Ditanya : % kelimpahan ke2 isotop
Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7
Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.
~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"
2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%
Ditanya: Massa rata**nya
Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%
5992,56+14448,4
= _________________
100%
20440,96
= ________
100%
= "204,4096"
Inggrid Kristiadi X 4 / 17
Nama: Gloria Y.P
Kls/No :x-1/18
1. diket : Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tny : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
krn no.massanya sama,maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan ke2 isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
Lanjutan Komentar sebelumnya...
2. Jwb:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
. Diket: Ar rata*: 9,941 sma
massa Li-6 massa li-7 =
6,939
Tanya: Persen kelimpahan ke 2 isotop?
Jawab: Ar rata*=(Ar1.P%)+(Ar2.9%)
Ar1= massa Li-6=6,939
P%= Persen kelimpahan Li-6
Ar2= massa Li-7=6,939
9%= Persen kelimpahan Li-7
Karena no. massa sama, mka kelimpahan ke 2 isotop juga sama.
N%= Persen kelimpahan ke 2 isotop
9,941=(6,939N%)+(6,939N%)
9,9
Lanjutan no 1..
9,941=13,878N%
N%= 9,941:13,878
=0,72
2. Diket: TL-203=29,52%
TL-205=70,48%
Ditanya: Massa rata*nya?
Jawab: 29,52%.203+70,48.205
____________________
29,52%+70,48
=5992,56+14448,4
________________
100%
=20440,96
________
100
=204,4096
laurensia karina astriani
X-1/24
1.
Diket : ~Ar rata2=9,941 sma
~massaLi-6=massaLi-7=6,939
Ditanya : % kelimpahan ke2 isotop
Jwb :
Ar rata2=(Ar1xp%)+ (Ar2xq%)
~Ar1 = massa Li-6 = 6,939
~P% = persen kelimpahan Li-6
~Ar2 = massa Li-7 = 6,939
~Q% = persen kelimpahan Li-7
Krn no.massanya sama,maka
% kelimpahan kedua isotop juga sama.
~N%=persen kelimpahan ke2 isotop
9,941 =(6,939N%)+(6,939N%)
9,941 =13,878N%
N% =9,941 : 13,878
N% ="0,72"
2.
Diket : ~TL-203 = 29,52%
~TL-205 = 70,48%
Ditanya: Massa rata**nya
Jwb:
29,52%.203 + 70,48.205
= ______________________
29,52%+70,48%
5992,56+14448,4
= _________________
100%
20440,96
= ________
100%
= "204,4096"
By:Prissa Anita A
X-2/33
1.
Diketahui :
Ar rata2=9,941 sma
massa Li-6=massa Li-7=6,939
tanya : persen kelimpahan ke2 isotop=?
jwb : ar rata2=(Ar 1xp%)+ (Ar2 xq%)
*Ar1 = massa Li-6=6,939
*p% =persen kelimpahan Li-6
*Ar2 = massa Li-7 =6,939
*q% =persen kelimpahan Li-7
karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama:
n%=persen kelimpahan kedua isotop
9,941=(6,939n%)+(6,939n%)
9,941=13,878n%
n% =9,941 : 13,878
n% =0,72
2.
Jawab:
= 29,52%.203+70,48.205
__________________________
29,52%+70,48%
= 5992,56+14448,4
____________________
100%
= 20440,96
_____________
100%
= 204,4096
1. dik: Ar rt2= 9,941 sma
Li-6= Li-7 =6,939
dit: %klimphn ke-2 isotop
jwb: Ar rt2=(Ar1.p%)+(Ar2.9%)
Ar1= massa Li-6=6,939
p% = %klimphn Li-6
Ar2= massa Li-7=6,939
9% = %klimphn Li-7
klimphn 2 isotop sm krn no. massanya sm.
N% = %klimphn ke-2 isotop
9,941= (6,939N%)+(6,939N%)
9,941= 13,878N%
N% = 0,72
2. dik: TL-203=29,52%
TL-205=70,48%
DIT: msa rt2
jwb: 29,52%.203 + 70,48.205
______________________
29,52% + 70,48%
= 5992,56 + 14448,4
______________________
100%
= 20,4096
_________
100%
=204,4096
marlene g.i x-2
Isabella Lupita
X-2/21
1.Diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7
Karena nomor massanya sama,maka persen kelimpahan kedua isoytop juga sama.a
n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72
2. Diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%
5992,56 + 14448,4
= ______________________
100%
20440,96
=___________
100%
=204,4096
Jasmine Hutama G.
X-2/21
1.Diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7
Karena nomor massanya sama,maka persen kelimpahan kedua isoytop juga sama.a
n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72
2. Diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%
5992,56 + 14448,4
= ______________________
100%
20440,96
=___________
100%
=204,4096
Jasmine Hutama G.
X-2/21
1.Diketahui: Ar rata2=9,941 sma massa Li-6 = massa Li-7=6,939
Dit = persen kelimpahan kedua isotop
jwb=
Ar rata2 = (Ar1 x p%)+(Ar2 x q%)
Ar 1 =massa Li-6=6,939
p% = persen kelimpahan Li-6
Ar2= massa Li-7 = 6,939
q% = persen kelimpahan Li-7
Karena nomor massanya sama,maka persen kelimpahan kedua isoytop juga sama.a
n%=persen kelimpahan kedua isotop
9,941=(6,939 n%)+(6,939 n%)
9,941=13,878 n%
n% = 9,941 : 13,878
n%=0,72
2. Diketahui: TL-203=29,52%
TL-205=70,48%
dit : massa rata2nya
jwb:
29,52%.203+70,48%.205
= ____________________________
29,52% + 70,48%
5992,56 + 14448,4
= ______________________
100%
20440,96
=___________
100%
=204,4096
1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7
Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72
2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%
= 5992,56+14448,4
-----------------
100%
= 20440,96
------------
100%
= 204,4096
1.)DIKETAHUI = Ar rata-rata = 9,941 sma massa Li-6 = massa Li-7=6,939
DITANYAKAN = persen kelimpahan ke 2isotop = ?
JAWAB =
Ar rata-rata = (Ar 1xp%)+ (Ar2 xq%)
~ Ar1 = Massa Li-6 = 6,939
~ p% = Persen kelimpahan Li-6
~ Ar2 = Massa Li-7 = 6,939
~ q% = Persen kelimpahan Li-7
Karena nomor massanya sama, maka persen kelimpahan kedua isotop juga sama =
~ n% = persen kelimpahan ke2 isotop
9,941 = (6,939n%)+(6,939n%)
9,941 = 13,878n%
~ n% = 9,941 : 13,878
n% = 0,72
2.)Diketahui = TL-203 = 29,52%
TL-205 = 70,48%
Ditanya = Massa rata-rata
Jawab =
= 29,52%.203+70,48.205
------------------------
29,52%+70,48%
= 5992,56+14448,4
-----------------
100%
= 20440,96
------------
100%
= 204,4096
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