Jika 38 gram garam MgSO4.xH20 dipanaskan menghasikan 20 gram garam anhidrat sesuai dengan persamaan reaksi MgSO4.xH2O --> MgSO4 + xH2O. Jika Mr MgSO4=120, H2O=18 tentukan nilai x !
14 komentar:
Anonim
mengatakan...
Angela Nathania x-i / 05
Jawab: MgSO4.xH2O --> MgSO4 + xH2O 38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4 =38g-20g =18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4 =20g : 120g = 1/6 mol
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14 komentar:
Angela Nathania
x-i / 05
Jawab:
MgSO4.xH2O --> MgSO4 + xH2O
38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4
=38g-20g
=18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4
=20g : 120g
= 1/6 mol
Jumlah mol H2O=Massa H2O : Mr H2O
=18 : 18
= 1mol
(Jumlah mol MgSO4/Jumlah mol H2O) = (Koef MgSO4/Koef H2O)
(1/6)/1 = 1/x
1/6 = 1/x
x = 6
MgSO4 . XH2O => MgSO4 + XH2O
38 g 20g
m H2O = m MgSO4 . X H2O – m MgSO4
= 38 g – 20 g
= 18 g
Jumlah mol MgSO4 = m MgSO4/Mr MgSO4
= 20/120
= 1/6 mol
Jumlah mol H2O = m Mr H2O
= 18/18
= 1 mol
Jumlah mol MgSO4 : jumlah mol H2O = koefisiensi MgSO4 : koefisiensi XH2O
1/6 : 1 = 1 : X
1/6 X = 1
X = 6
Jumlah molekul hidrat = 6
deta
x-1
Jawab:
MgSO4.xH2O --> MgSO4 + xH2O
38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4
=38g-20g
=18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4
=20g : 120g
= 1/6 mol
Jumlah mol H2O=Massa H2O : Mr H2O
=18 : 18
= 1mol
(Jumlah mol MgSO4/Jumlah mol H2O) = (Koef MgSO4/Koef H2O)
(1/6)/1 = 1/x
1/6 = 1/x
x = 6
jemmy
x-1
Jawab:
MgSO4.xH2O --> MgSO4 + xH2O
38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4
=38g-20g
=18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4
=20g : 120g
= 1/6 mol
Jumlah mol H2O=Massa H2O : Mr H2O
=18 : 18
= 1mol
(Jumlah mol MgSO4/Jumlah mol H2O) = (Koef MgSO4/Koef H2O)
(1/6)/1 = 1/x
1/6 = 1/x
x = 6
Kharisma endianto /X-1/25
MgSO4.xH2O --> MgSO4 + xH2O
38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4
=38g-20g
=18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4
=20g : 120g
= 1/6 mol
Jumlah mol H2O=Massa H2O : MrH2O
= 18 : 18
= 1mol
(Jumlah mol MgSO4/Jumlah mol H2O) = (Koefisien MgSO4/Koefisien H2O)
(1/6)/1 = 1/x
(1/6) = 1/x
x = 6
Christian S/X-1/10
MgSO4.xH2O --> MgSO4 + xH2O
38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4
=38g-20g
=18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4
=20g : 120g
=1/6 mol
Jumlah mol H2O=Massa H2O : Mr H2O
=18 : 18
=1mol
(Jumlah mol MgSO4/Jumlah mol H2O)=(Koef MgSO4/Koef H2O)
(1/6)/1 = 1/x
1/6 = 1/x
x = 6
MgSO4.xH2O --> MgSO4 + xH2O
38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4
=38g-20g
=18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4
=20g : 120g
= 1/6 mol
Jumlah mol H2O=Massa H2O : Mr H2O
=18 : 18
= 1mol
(Jumlah mol MgSO4/Jumlah mol H2O) = (Koef MgSO4/Koef H2O)
(1/6)/1 = 1/x
1/6 = 1/x
x = 6
Yohanes X1/42
Amadea
x-1 /07
MgSO4.xH2O => MgSO4 + xH2O
38g 20g
Massa H2O=massa MgSO4.xH2O - massa MgSO4
= 38g - 20g mol
= 18g
Jumlah mol MgSO4=massa MgSO4 : Mr MgSO4
= 20g : 120g mol
= 1/6 mol
Jumlah mol H2O=massa H2O : Mr H2O
= 18g : 18g mol
= 1 mol
Jumlah mol MgSO4 : Jumlah mol H2O = Koefisien MgSO4 : Koefisien H2O
1/6 : 1 = 1 : x
1/6x = 1
x = 6
Jumlah molekul hidrat = 6
Andre Setiawan (xi/04)
MgSO4.xH2O => MgSO4 + xH2O
38g 20g
massa H2O=massa MgSO4.xH2O - massa MgSO4
= 38g - 20g
= 18g
Jumlah mol MgSO4=massa MgSO4 : Mr MgSO4
= 20g : 120g
= 1/6mol
Jumlah mol H2O=massa H2O : Mr H2O
= 18g : 18g
= 1mol
Jumlah mol MgSO4:Jumlah mol H2O = Koefisien MgSO4:Koefisien H2O
1/6 : 1 = 1 : x
1/6x = 1
x = 6
Jumlah molekul hidrat = 6
MgSO4.xH2O --> MgSO4 + xH2O
38g 20g
Mssa H2O=Mssa MgSO4.xH2O-mssa MgSO4
=38g-20g
=18g
Jumlah mol MgSO4=Mssa MgSO4:MrMgSO4
=20g : 120g
= 1/6 mol
Jumlah mol H2O=Massa H2O : Mr H2O
=18 : 18
= 1mol
(Jumlah mol MgSO4/Jumlah mol H2O) = (Koef MgSO4/Koef H2O)
(1/6)/1 = 1/x
1/6 = 1/x
x = 6
MgSO4 . XH2O => MgSO4 + XH2O
38 g 20g
m H2O = m MgSO4 . X H2O – m MgSO4
= 38 g – 20 g
= 18 g
Jumlah mol MgSO4 = m MgSO4/Mr MgSO4
= 20/120
= 1/6 mol
Jumlah mol H2O = m Mr H2O
= 18/18
= 1 mol
Jumlah mol MgSO4 : jumlah mol H2O = koefisiensi MgSO4 : koefisiensi XH2O
1/6 : 1 = 1 : X
1/6 X = 1
X = 6
Jumlah molekul hidrat = 6
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